If you are running Docker For Windows, the following will work:
echo off&for /f “delims=” %A in ('docker images -f “dangling=true” -q ') do docker rmi %A & echo on
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If you are running Docker For Windows, the following will work:
echo off&for /f “delims=” %A in ('docker images -f “dangling=true” -q ') do docker rmi %A & echo on
To remove all images which aren’t associated with a running container:
docker image prune -a
The -a parameter is the crucial bit here.
If you want to force the action to occur without a confirmation prompt, you may add the -f parameter, like so:
docker image prune -af
Note: -af is the same as specifying -a and -f separately
If you are like me and keep trying out interactive terminal sessions on images all the time, you will see a lot of : images in the list. They are all linked to stopped containers that you used earlier. Cleanup containers and then cleanup images
docker container prune
docker image prune
sudo docker images
sudo docker rmi -f <$imageID>
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On windows, create a new batch file and add the following command,
FOR /f “tokens=*” %%i IN (‘docker images -f “dangling=true” -q’) DO docker rmi %%i -f
This works on my end. Removing all or unused images.
Docker rmi $(docker images -a -q)
use
docker rmi (docker images -f “dangling=true” -q )
docker rmi $(docker images -f dangling=true -q )
Removing the double quotes from the dangling options solves the problem
received the response while trying with this command. Tag and repositories might be linked to some active repositories.
Command:
docker rmi $(docker images -a|grep "<none>"|awk '$1=="<none>" {print $3}')
Response:
Error response from daemon: conflict: unable to delete f039e1783673 (cannot be forced) - image has dependent child images
sometimes we may need “f” for forcing to remove containers
I’ve came across the same problem and have written a solution on Stack Overflow, which I will reproduce here.
You can label the intermediate images and docker image prune
those images based on this label.
Dockerfile (using multi-stage builds)
FROM node as builder
LABEL stage=builder
...
FROM node:dubnium-alpine
...
After you’ve built you image, run:
$ docker image prune --filter label=stage=builder
If you are running the builds in an automation server (e.g. Jenkins), and want to remove only the intermediate images from that build, you can
ARG
instruction for this build ID inside your Dockerfile
docker build
through the --build-arg
flagFROM node as builder
ARG BUILD_ID
LABEL stage=builder
LABEL build=$BUILD_ID
...
FROM node:dubnium-alpine
...
$ docker build --build-arg BUILD_ID .
$ docker image prune --filter label=stage=builder --filter label=build=$BUILD_ID
If you want to persists the build ID in the image (perhaps as a form of documentation accessible within the container), you can add another ENV
instruction that takes the value of the ARG
build argument. This also allows you to use the similar environment replacement to set the label value to the build ID.
FROM node as builder
ARG BUILD_ID
ENV BUILD_ID=$BUILD_ID
LABEL stage=builder
LABEL build=$BUILD_ID
...
FROM node:dubnium-alpine
...
This worked for me
docker rmi <image_ID> -f
Then you’ll see:
Deleted: sha256:e23dfs4hlkjlkjsdflksjdfosdflksdjf2rf239fi932i09329f0i2390if2903f0239f
sudo docker image rm cd14cecfdb3a -f
--force-rm
seems to prevent leaving <none>:<none> images when I use docker-compose to build images like so:
docker-compose build --force-rm
I don’t know why it works. The doc (https://docs.docker.com/compose/reference/build/) says --force-rm always remove intermediate containers
but not images
.
This works for me.
docker image prune -f
docker images -f "dangling=true" -q
lists one image per row, and docker rmi
expects them to be separated by space rather than newline, so you have to join them together before calling docker rmi
if there are multiple images that need to be removed. This is the command that works for me:
docker rmi $(docker images -f "dangling=true" -q | tr "\n" " ")
Thanks! Copy-paste does not work because of the quotes. But the code works anyhow.
you are right, but need in the powershell
Great.also has this problem.
thanks for it