Command to check docker image size

General
1

I am using following command to build the image:

 $TOKEN = $(az acr login --name acr11908e1dv01.azurecr.io --expose-token --output tsv --query accessToken)
      
docker login acr11908e1dv01.azurecr.io -u 00000000-0000-0000-0000-000000000000 -p $TOKEN
      
cd ./Docker

docker image build --build-arg AUSER=$(AUSER) --build-arg APASS=$(APASS) --file Dockerfile . -t acr11908e1dv01.azurecr.io/docker-linux-agent:$(Build.BuildNumber)

if (("$(Build.SourceBranch)". ToLower(). Contains("master")) -or ("$(Build.SourceBranch)". ToLower(). Contains("develop")))
        {
           docker push acr11908e1dv01.azurecr.io/docker-linux-agent:$(Build.BuildNumber)
        }
      docker logout

amd then I am trying to use following command to check the size of the image which was developed using above command :slight_smile:

IMAGE_NAME=“acr11908e1dv01.azurecr.io/docker-linux-agent:$(Build.BuildNumber)”
TAG=“$(Build.BuildNumber)”
SIZE=$(docker images --format “{{. Size}}” ${IMAGE_NAME}😒{TAG})
echo “The size of the image ${IMAGE_NAME}😒{TAG} after build is ${SIZE}.”

But i am not fetching ant size. Please suggest how we can fetch size of the image in my case?

2

The command looks fine, except there’s a space after the dot in "{{.Size}}", without the space the command seems to work fine

3

After removing space also it is giving same message which is not giving size of the image

4

That message being what?

5

Below is the message:

The size of the image acr11908e1dv01.azurecr.io/docker-linux-agent:ubi9-11908-v1.0.58:ubi9-11908-v1.0.58 after build is .